2x^2+4(x^2+3)-2=22

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Solution for 2x^2+4(x^2+3)-2=22 equation: 


Simplifying
2x2 + 4(x2 + 3) + -2 = 22

Reorder the terms:
2x2 + 4(3 + x2) + -2 = 22
2x2 + (3 * 4 + x2 * 4) + -2 = 22
2x2 + (12 + 4x2) + -2 = 22

Reorder the terms:
12 + -2 + 2x2 + 4x2 = 22

Combine like terms: 12 + -2 = 10
10 + 2x2 + 4x2 = 22

Combine like terms: 2x2 + 4x2 = 6x2
10 + 6x2 = 22

Solving
10 + 6x2 = 22

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + 6x2 = 22 + -10

Combine like terms: 10 + -10 = 0
0 + 6x2 = 22 + -10
6x2 = 22 + -10

Combine like terms: 22 + -10 = 12
6x2 = 12

Divide each side by '6'.
x2 = 2

Simplifying
x2 = 2

Take the square root of each side:
x = {-1.414213562, 1.414213562}

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